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Basic Buffer Action

A buffer solu...

Question

A buffer solution with $p H = 9$ is to be prepared by mixing $N H_{4} C l$ and $N H_{4} O H$ . Calculate the number of moles of $N H_{4} C l$ that should be added to $1$ liter of $1 M N H_{4} O H . K_{b} (N H_{4} O H) = 1.8 \times 10^{- 5}$ .

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Solution

Its a basic buffer $p H = 9; p O H = 5$
$p O H = p K_{b} + l o g [\frac{(S a l t)}{(B a s e)}]$
$5 = - l o g (108 \times 10^{- 5}) + l o g [\frac{{N H}_{4} C l}{{N H}_{4} O H}]$
$5 = 4.745 + l o g [N H_{4} C l]$
no. of Moles of $N H_{4} C l$ added $= 1.8$

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