Question

A building block has a square base that has a perimeter of $(12x-9)$inches. Explain how to use the expression to find the length (in inches) of the wall shown.

Answer 1

Hint: Perimeter of the square = $4\times side$

Given:

The perimeter of the square base =$(12x-9)$ inches

As we know the Perimeter of the square = $4\times side$

Equating both we get

$4\times$length of the square base = $(12x-9)$

length of the square base = $\frac{1}{4}(12x-9)$

length of the square base = $\left(3x-\frac{9}{4}\right)$ inches

Now from the given figure we can see that there are 7 blocks in whole length of the wall.

The length of wall = $7\times$length of the square base

The length of wall =$=7\times \left(3x-\frac{9}{4}\right)$

Hence the length of wall is $7\times \left(3x-\frac{9}{4}\right)$