A building is $24 m 8 c m$ high. Four pipes of equal length joined together run from the roof of the building to the ground. What is the length of each pipe?

Open in App

Solution

Given:
Length of the building = $24 m 8 c m$
Four pipes are used for covering the length of the building
Length of each pipe
= $24 m 8 c m$
= $(2400 c m + 8 c m) \div 4 (1 m = 100 c m)$
= $(2408 \div 4) c m$
= $602 c m$
= $6 m 2 c m$
Hence, the length of each pipe is $6 m 2 c m .$

Suggest Corrections

Similar questions

A building is 24 m 8 cm high. Four pipes of equal length joined together ,running from the roof of the building to the ground. What is the length of each pipe?

Q. Alex climbs down six floors of a building from its terrace. If the building is 120 m high and each floor is 8 m high, how high is he from the ground?

The length of a string between a kite and a point on the roof of a building 10 m high is 180 m. If the string makes an angle A with the level ground such that tan A = $\frac{4}{3}$ . How high is the kite from the ground?

Q. Two equal pipes each having length of 6 m and 813 cm joined by welding and then a
small piece 85 cm is cut from the whole. What is the remaining length of the
pipe?

Join BYJU'S Learning Program

A building is 24m8cmhigh. Four pipes of equal length joined together run from the roof of the building to the ground. What is the length of each pipe?

Given: Length of the building = 24m8cmFour pipes are used for covering the length of the buildingLength of each pipe =24m8cm= (2400cm+8cm)÷4(1m=100cm)= (2408÷4)cm= 602cm= 6m2cmHence, the length of each pipe is 6m2cm.

A building is $24 m 8 c m$ high. Four pipes of equal length joined together run from the roof of the building to the ground. What is the length of each pipe?

Given:
Length of the building = $24 m 8 c m$
Four pipes are used for covering the length of the building
Length of each pipe
= $24 m 8 c m$
= $(2400 c m + 8 c m) \div 4 (1 m = 100 c m)$
= $(2408 \div 4) c m$
= $602 c m$
= $6 m 2 c m$
Hence, the length of each pipe is $6 m 2 c m .$