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Question

A bulb  is connected to a battery of p.d. 4 V and internal resistance 2.5 Ω. A steady current of 0.5 A flows through the circuit. Calculate :

(i) the total energy supplied by the battery in 10 minutes,

(ii) the resistance of the bulb, and 

(iii) the energy dissipated in the bulb in 10 minutes.


Solution

Given,
Voltage, V=4 V
Resistance space of space the space battery comma R subscript B equals 2.5 space o h m c u r r e n t space comma space I equals 0.5 space A left parenthesis i right parenthesis E n e r g y space s u p p l i e d space b y space t h e space b a t t e r y comma E equals fraction numerator V squared t over denominator R end fraction t equals 10 cross times 60 equals 600 space s e c R equals V over I equals fraction numerator 4 over denominator 0.5 end fraction equals 8 space o h m E equals fraction numerator 4 squared cross times 600 over denominator 8 end fraction equals 1200 J left parenthesis ii right parenthesis T o t a l space r e s i s tan c e comma space R equals 8 space o h m R e s i s tan c e space o f space t h e space b a t t e r y comma R subscript B equals 2.5 space o h m R e s i s tan c e space o f space t h e space b u l b comma R subscript b equals 8 minus 2.5 equals 5.5 space o h m left parenthesis iii right parenthesis E n e r g y space d i s s i p a t e d space i n space t h e space b u l b space i n space 10 space m i n comma E equals I squared R t space equals 0.5 squared cross times 5.5 cross times 600 equals 825 J

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