Question

A bulb is placed between two plane mirrors inclined at an angle of ${60}^0$.The number of images formed is :

• A. $5$
• B. $6$
• C. $4$
• D. $3$

Answer 1

The correct option is A $5$

As $\frac{{360}^0}{\theta }=\frac{{360}^0}{{60}^0}=6$ (which is even)

$\Rightarrow n=\frac{{360}^0}{\theta }-1=6-1=5$