A bulb is rated 5 V and 500 mA. Calculate its (a) power, (b) resistance, and (c) energy consumed when it is lighted for 4 hours.

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Solution

(a) Power = P = VI
$= 5 \times 0.5 = 2.5 W$
(b) Resistance (R) $= \frac{V}{I} = \frac{5}{0.5} = 10 Ω$
(c) Energy consumed = $V I t = P \times t$
$E = 2.5 \times 4 \times 3600 J$
$E = 36000 J$
$E = 36 k J$

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A bulb is rated 5 V and 500 mA. Calculate its (a) power, (b) resistance, and (c) energy consumed when it is lighted for 4 hours.

(a) Power = P = VI =5×0.5=2.5W(b) Resistance (R) =VI=50.5=10 Ω(c) Energy consumed =VIt=P×t E=2.5×4×3600JE=36000JE=36 kJ

(a) Power = P = VI
$= 5 \times 0.5 = 2.5 W$
(b) Resistance (R) $= \frac{V}{I} = \frac{5}{0.5} = 10 Ω$
(c) Energy consumed = $V I t = P \times t$
$E = 2.5 \times 4 \times 3600 J$
$E = 36000 J$
$E = 36 k J$