A bulb is rated at 200V,40W. What is the resistance? 5 such bulbs are lighted for 5 hours. Calculate the electrical energy consumed. Find the cost if the rate is Rs 5.10 per kWh

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Solution

V= 200V
P=40W
P=V^2/R
R=V^2/P
=200×200/40= 1000ohm
TOT P=5×40=200W =0.2kW
E=0.2×5=1kWh
Cost=Rs5.10

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A bulb is rated at 200V,40W. What is the resistance? 5 such bulbs are lighted for 5 hours. Calculate the electrical energy consumed. Find the cost if the rate is Rs 5.10 per kWh

V= 200V P=40W P=V^2/R R=V^2/P =200×200/40= 1000ohm TOT P=5×40=200W =0.2kW E=0.2×5=1kWh Cost=Rs5.10

V= 200V
P=40W
P=V^2/R
R=V^2/P
=200×200/40= 1000ohm
TOT P=5×40=200W =0.2kW
E=0.2×5=1kWh
Cost=Rs5.10