A bulb is rated at 5V, 100mA. Calculate its (1) Power (2) Resistance

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Solution

Given : $V = 5 v o l t s$ $i = 100 m A = 0.1 A$
(a) : Power $P = V i = 5 \times 0.1 = 0.5 w a t t$
(b) : Resistance $R = \frac{V^{2}}{P} = \frac{5^{2}}{0.5} = 50 Ω$

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A bulb is rated at 5V, 100mA. Calculate its (1) Power (2) Resistance

Given : V=5 volts i=100 mA=0.1 A(a) : Power P=Vi=5×0.1=0.5 watt(b) : Resistance R=V2P=520.5=50 Ω

Given : $V = 5 v o l t s$ $i = 100 m A = 0.1 A$
(a) : Power $P = V i = 5 \times 0.1 = 0.5 w a t t$
(b) : Resistance $R = \frac{V^{2}}{P} = \frac{5^{2}}{0.5} = 50 Ω$