Question

A bulb of 1 $d{m}^3$ capacity can withstand a maximum pressure of 10 bars. If contains 14 g of nitric oxide, at what temperature , the bulb will reach the bursting limit?

• A. -15. 72${}^{\circ }C$
• B. -18.6 ${}^{\circ }C$
• C. -20 ${}^{\circ }C$
• D. 15.72 ${}^{\circ }C$

Answer 1

The correct option is A -15. 72${}^{\circ }C$

Given ,

P = 10 bars = 9.86923 atm {1 bar = 0.9869 atm}

Mol. mass of NO = 30 gm

n = $\frac{14}{30}$ (number of moles)

volume = $1d{m}^3$ = 1 L

$\therefore$ T = ?

As we know , from gas law

PV = nRT

$T=\frac{PV}{nR}$

$T=\frac{9.86\times 1}{\left(\frac{14}{30}\right)\times 0.0821}=257.03K$

$T=(257.03-273{)}^{0}C$

$\therefore T=-{15.72}^{0}C$

No option is correct .