Question

A bulb of unknown volume V contains a gas at 1 atm pressure.This bulb was connected to another evacuated bulb of volume 0.5 L through a stop cock.When the stop cock was opened ,the pressure at each bulb became 7.58×10⁴ Pa mm while the temperature remained constant. Calculate V in L.
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Answer 1

Step 1:

1 atm = 101325 Pa

P₁V₁ = P₂V₂

101325 x V = 7.58 x 10⁴ x (V + 0.5)

Step 2:

101325V - 75800V = 37900

V = 37900/25525

V = 1.48 L

Hence, the volume is 1.48 L.