Question

A bulb of unknown volume 'V' contains an ideal gas at 2 atm pressure. It was connected to another evacuated bulb of volume 0.5 litre through a stopcock.When the stopcock was opened the pressure in each bulb became 0.5 atm. Then V is:

• A. 17 ml
• B. 1.7 litres
• C. 0.17 litres
• D. 0.34 litres

Answer 1

The correct option is C 0.17 litres

Given that,

$P_1=2atm;P_2=0.5atm;V_1=V$ and $V_2=(V+0.5)L$

$\because P_2{V}_2=P_1{V}_1$ $($When temperture is constant $P\propto 1/V)$

$0.5(0.5+V)=2\times V$

$0.25+0.5V=2V$

$1.5V=0.25$

$V=\frac{0.25}{1.5}=0.17L$

Hence, the correct option is $C$.