A bullet cart system have total mass $50 m$ Where $^{'} m^{'}$ is mass of each bullet. If bullet fired with velocity $v m / s e c$ with respect to cart then, find velocity of cart system after second shot.

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Solution

Applying the conservation of momentum after first shot, we get
$0 + 0 = m v + 49 m v^{'}$
$v^{'} = - \frac{v}{49} m / s$
Now, the initial momentum of cart before the second shot is $49 m v^{'}$ .
Applying the conservation of momentum after the second shot, we get
$0 + 49 m v^{'} = m v + 48 m v^{''}$
$49 (- \frac{v}{49}) = m v + 48 m v^{''}$
$v^{''} = - \frac{v}{24} m / s$

Thus, the velocity of cart after the second shot is $\frac{v}{24} m / s$ .

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A bullet cart system have total mass 50m Where ′m′ is mass of each bullet. If bullet fired with velocity vm/sec with respect to cart then, find velocity of cart system after second shot.

A bullet cart system have total mass $50 m$ Where $^{'} m^{'}$ is mass of each bullet. If bullet fired with velocity $v m / s e c$ with respect to cart then, find velocity of cart system after second shot.