Question

A bullet comes out of the barrel of gun of length $2m$ with a speed $80m/s$. The average acceleration of the bullet is

• A. $1.6m/s^2$
• B. $160m/s^2$
• C. $1600m/s^2$
• D. $16m/s^2$

Answer 1

The correct option is C

$1600m/s^2$

Step 1: Given data

Length of the gun, $s$$=2m$

The final velocity of the bullet, $v=80m/s$

The initial velocity of the bullet, $u=0m/s$

Step 2: Formula used

From equation of motion:

$v^2=u^2+2*a*s$

where $v$is the final velocity, $u$ is the initial velocity, $a$ is the acceleration achieved, $s$ is the distance traveled.

Step 3: Find the acceleration of the bullet

Substitute the values of $v,u$and $s$

$$\begin{gathered} v^2=u^2+2*a*s \\ \Rightarrow {80}^2=0^2+2*a*2 \\ \Rightarrow a=6400/4 \\ \Rightarrow a=1600m/s^2 \end{gathered}$$

Hence, the acceleration of the bullet is $1600m/s^2$. Option C is correct.