wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A bullet fired horizontally with a speed of 400 m/sec. It strikes a wooden block of mass 2 kg hanging vertically with the help of long string. After striking with bullet, block rises a height of 20 cm. If speed with which bullet emerges out from block is 10 λ then find λ. Mass of bullet is 20 gm. (take g=10 m/s2)

Open in App
Solution

Given mass of wooden block M=2kg and mass of bullet , m=20gm=0.02kg
Let speed of wooden block after collision is v. Block rises by h=20cm=0.2m
Using conservation of mechanical energy, KE1+PE1=KE2+PE2
12mv2+0=0+mgh v=2gh=2×10×0.2=2m/s

There are no external force are acting so momentum will be conserved.
Linear momentum before collision = Linear Momentum after collision
0.02×400+2×0=0.02×10λ+2×2
λ=10

flag
Suggest Corrections
thumbs-up
3
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon