A bullet hits a wall with a velocity of 20 metres per second and penetrates a distance of 5 cm find the deacceleration in bullet by the wall

Open in App

Solution

U= 20 m/s
v= 0
s = 5 cm = 0.05 m

from 3rd equation,
v² -u² = 2as
⇒0 - (20)² = 2×0.05×a
⇒0.1 a = - 400
⇒a = - 4000 m/s²

deceleration will be - 4000 m/s²

Suggest Corrections

Similar questions

A bullet hits a wall with a velocity of 20m/s and penetrates it up to a distance of 5 cm. Find the deceleration of the bullet in the wall.

A bullet is fired into a wall with a velocity of 50 M per second. If the Bullet stops at the depth of 10 cm inside the wall find find the retardation provided by the wall

Q. N bullets each of mass

m k g

are fired with a velocity

v m s^{- 1}

at the rate of n bullets per second upon a wall. The reaction offered by the wall to the bullets is given by

Q. A bullet going with speed 350 m/s enters a concrete wall and penetrates a distance of 5.0 cm before coming to rest. Find the deceleration.

Join BYJU'S Learning Program

A bullet hits a wall with a velocity of 20 metres per second and penetrates a distance of 5 cm find the deacceleration in bullet by the wall

U= 20 m/s v= 0 s = 5 cm = 0.05 m from 3rd equation, v² -u² = 2as ⇒0 - (20)² = 2×0.05×a ⇒0.1 a = - 400 ⇒a = - 4000 m/s² deceleration will be - 4000 m/s²

U= 20 m/s
v= 0
s = 5 cm = 0.05 m

from 3rd equation,
v² -u² = 2as
⇒0 - (20)² = 2×0.05×a
⇒0.1 a = - 400
⇒a = - 4000 m/s²

deceleration will be - 4000 m/s²