A bullet initially moving with a velocity $20 m s^{- 1}$ strikes a target and comes to rest after penetrating a distance $10 c m$ in the target .Calculate the retardation caused by the target.

1000 m / s^{2}

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2000 m / s^{2}

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3000 m / s^{2}

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4000 m / s^{2}

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Solution

The correct option is B. $2000 m / s^{2}$
Given,
$u = 20 m / s$
$s = 10 c m = 0.1 m$
$v = 0 m / s$
From 3rd equation of motion,
$2 a s = v^{2} - u^{2}$
$a = \frac{v^{2} - u^{2}}{2 s} = \frac{0^{2} - 20 \times 20}{2 \times 0.1}$
$a = - 2000 m / s^{2}$
Negative sign means it is retardation.
The correct option is B.

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A bullet initially moving with a velocity 20ms−1 strikes a target and comes to rest after penetrating a distance 10cm in the target .Calculate the retardation caused by the target.

The correct option is B. 2000m/s2Given,u=20 m/ss=10 cm=0.1 mv=0 m/sFrom 3rd equation of motion,2as=v2−u2a=v2−u22s=02−20×202×0.1a=−2000 m/s2Negative sign means it is retardation.The correct option is B.

A bullet initially moving with a velocity $20 m s^{- 1}$ strikes a target and comes to rest after penetrating a distance $10 c m$ in the target .Calculate the retardation caused by the target.