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Standard XII

Physics

Instantaneous Velocity

A bullet is f...

Question

A bullet is fire with a velocity $u$ making an angle of $60^{o}$ with the horizontal plane. The horizontal component of the velocity of the bullet when it reaches the maximum height is:

u

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0

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\frac{\sqrt{3 u}}{2}

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u / 2

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Solution

The correct option is D $u / 2$
Given,
$θ = 60^{0}$
From the above figure,
At maximum height,
The vertical component of the initial velocity,
$u_{y} = 0 m / s$
The horizontal component of the initial velocity,
$u_{x} = u c o s 60^{0}$
$u_{x} = u \times \frac{1}{2}$
$u_{x} = \frac{u}{2}$
The correct option is D.

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A bullet is fire with a velocity u making an angle of 60o with the horizontal plane. The horizontal component of the velocity of the bullet when it reaches the maximum height is:

The correct option is D u/2Given,θ=600From the above figure,At maximum height, The vertical component of the initial velocity,uy=0m/sThe horizontal component of the initial velocity,ux=ucos600ux=u×12ux=u2The correct option is D.

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