Question

A bullet is fired at an angle of ${15}^{\circ }$ with the horizontal and hits the ground 6 km away. Is it possible to hit a target 10 km away by adjusting the angle of projection assuming the initial speed will be the same.

Answer 1

Range $R=u^{2}Sin2\theta /g=6000meter$

so $u^2=120000m/s$ so $u=346.4m/s$

Note, we used $Sin2\theta =Sin{30}^0=0.5$

Now we know that the maximum value of range is given as $R_{max}=u^2/g=120000/10=12000meter=12Km$

So its possible to hit the target at 10Km distance because its less than maximum range.