A bullet is fired from a canon with velocity 500 m - s- If the angle of projection is 15- and g -10 m - s 2- Then the range isA- 25 - 103 mB- 12-5 - 103 mC- 50 - 102 mD- 25 - 102 m

The correct option is B Range (R)=u^2 sin 2 θ/g=(500)^2 sin (2 × 15)/10=12500 m = 12.5 × 10^3m ...

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A bullet is fired from a canon with velocity 500 m/s. If the angle of projection is $15^{\circ}$ and $g = 10 m / s^{2}$ . Then the range is

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A bullet is fired from a cannon with velocity 500 m/s. If the angle of projection is $15^{\circ}$ and $g = 10 m / s^{2}$ . Then the range is

500

m / s

15^{o}

g = 10

m s^{- 2}

500 m

100 m / s

(g = 10 m / s^{2})

45^{o}

360 m

18 k m

h^{- 1}

g = 10 m s^{- 2}

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