A bullet is fired from a gun of 15 kg with a velocity of 100 m/s . If mass of the bullet is 50 gm what will be the velocity of the gun and in which direction.

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Solution

it is the application of conservation of momentum

let M1V1 be the momentum of gun M2V2 be the momentum of bullett

-M1V1 = M2V2 (- because in opposite direction )

-15V1 = 1005010^-3

V1 = -1005010^-3/15 = -0.33333 m/s in the opposite direction

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A bullet is fired from a gun of 15 kg with a velocity of 100 m/s . If mass of the bullet is 50 gm what will be the velocity of the gun and in which direction.

it is the application of conservation of momentum let M1V1 be the momentum of gun M2V2 be the momentum of bullett -M1V1 = M2V2 (- because in opposite direction ) -15V1 = 100*50*10^-3 V1 = -100*50*10^-3/15 = -0.33333 m/s in the opposite direction

it is the application of conservation of momentum

let M1V1 be the momentum of gun M2V2 be the momentum of bullett

-M1V1 = M2V2 (- because in opposite direction )

-15V1 = 1005010^-3

V1 = -1005010^-3/15 = -0.33333 m/s in the opposite direction