Question

A bullet is fired from the gun , held horizontally such that the velocity of the bullet is $200{ms}^{-1}$ and the gun is held 5 m above the ground. Find the horizontal distance covered by the bullet on reaching the ground $(Takeg=10{ms}^{-2})$

Answer 1

Given initial horizontal velocity $u=200{ms}^{-1}$
The verticle height , y = 5 m.
Let the time taken to cover 5m, =ts.
$g={10ms}^{-2}\therefore y=\frac{1}{2}{gt}^2\Rightarrow t^2=\frac{2y}{g}=\frac{2\times 5}{10}=1t=1s.\therefore Thehorizontaldistancecoveredin1s,x=ut=200\times 1=200m.$