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Question

A bullet is fired vertically upward with an initial velocity of 50 ms−1. If g=10 ms−2, what is the ratio of the distances travelled by the bullet during the first and last second of its upward motion ?

A
9:1
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B
9:2
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C
3:1
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D
9:4
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Solution

The correct option is A 9:1
As we know that the time taken to reach the maximum height is
t=ug=5010=5 sec
Also, displacement in nth sec is given as
Snth=u+a2[2n1]
As per the question we have
S1S5th=50102[2(1)1]50102[2(5)1]
S1S5th=5055045=455
S1S5th=91
Hence, the ratio is 9:1

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