A bullet leaves the rifle of mass one kg and the rifle recoils thereby with a velocity of 30 cm/s. If the mass of bullet is 3g, find the velocity of the bullet.

10 m / s

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100 m / s

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200 m / s

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50 m / s

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Solution

The correct option is A $100 m / s$
Mass of bullet is $= 3 g = 3 \times 10^{- 3} k g$
Mass of rifle $1 k g$
Recoil velocity = $30 c m / s = 0.3 m / s$
By conservation of linear momentum
$1 \times 0.3 = (3 \times 10^{- 3} k g) (v) v = 100 m / s$
Its the speed of the bullet
Option : B

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Similar questions

A rifle of mass 5 kg fires a bullet of mass 40 g. The bullet leaves the barrel of the rifle with a velocity 200 m/s. If the bullet takes 0.004 s to leave the barrel, calculate the following: (i) recoil velocity of the rifle and (ii) the force experienced by the rifle due to its recoil.

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. Find the final velocity of the recoil of the rifle.

A rifle of mass 5 kg fires a bullet of mass 40 gm. The bullet leaves the barrel of the rifle with a velocity 200 $\frac{m}{s}$ . If the bullet takes 0.004 s to move through the barrel, calculate the recoil velocity of the rifle.

Q. A bullet of mass 50 g is fiered from a rifle of mass 4 kg with initial velocity= 35 m/ s.what is the recoil velocity of the rifle ?

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A bullet leaves the rifle of mass one kg and the rifle recoils thereby with a velocity of 30 cm/s. If the mass of bullet is 3g, find the velocity of the bullet.

The correct option is A 100m/sMass of bullet is =3g=3×10−3kgMass of rifle 1kgRecoil velocity = 30cm/s=0.3m/sBy conservation of linear momentum 1×0.3=(3×10−3kg)(v)v=100m/s Its the speed of the bullet Option : B

The correct option is A $100 m / s$
Mass of bullet is $= 3 g = 3 \times 10^{- 3} k g$
Mass of rifle $1 k g$
Recoil velocity = $30 c m / s = 0.3 m / s$
By conservation of linear momentum
$1 \times 0.3 = (3 \times 10^{- 3} k g) (v) v = 100 m / s$
Its the speed of the bullet
Option : B