wiz-icon
MyQuestionIcon
MyQuestionIcon
1071
You visited us 1071 times! Enjoying our articles? Unlock Full Access!
Question

A bullet moving at 250 m/s penetrates 5 cm into a tree limb before coming to rest. Assuming that the force exerted by the tree limb is uniform, find its magnitude. Mass of the bullet is 10 g.

A
625 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6250 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
62.50 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6.250 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 6250 N
Given,
m=10g=0.01kg
u=250m/s
s=5cm=0.05m
v=0m/s
3rd equation of motion,
v2u2=2as
02(250)2=2×0.05×a
a=625000.1=625000m/s2
The magnitude of force exterted by the tree limb is,
F=ma
F=0.01×625000=6250N
The correct option is B.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Constant Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon