A bullet moving with a speed of 100 $m s^{- 1}$ can just penetrate into two planks of equal thickness. Then the number of such planks, if speed is doubled will be

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Solution

The correct option is C 8
When velocity is doubled KE will become 4 times as( $K E \propto v^{2}$ )
$∴$ bullet will go through $2 \times 4 = 8$ planks.

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A bullet moving with a speed of 100 ms−1 can just penetrate into two planks of equal thickness. Then the number of such planks, if speed is doubled will be

The correct option is C 8When velocity is doubled KE will become 4 times as(KE∝v2)∴ bullet will go through 2×4=8 planks.

A bullet moving with a speed of 100 $m s^{- 1}$ can just penetrate into two planks of equal thickness. Then the number of such planks, if speed is doubled will be

The correct option is C 8
When velocity is doubled KE will become 4 times as( $K E \propto v^{2}$ )
$∴$ bullet will go through $2 \times 4 = 8$ planks.