A bullet moving with a speed of $100 m s^{- 1}$ can just penetrate into two planks of equal thickness. Then, the number of such planks the bullet will penetrate, if speed is doubled will be

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Solution

The correct option is B 8
$\frac{1}{2} m v^{2} = n (F . d)$
$\Rightarrow n \propto v^{2}$
Thus,
If v is doubled, n will become four times.
Therefore the bullet will penetrate 8 planks.

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A bullet moving with a speed of 100ms−1 can just penetrate into two planks of equal thickness. Then, the number of such planks the bullet will penetrate, if speed is doubled will be

The correct option is B 812mv2=n(F.d)⇒n∝v2Thus,If v is doubled, n will become four times.Therefore the bullet will penetrate 8 planks.

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The correct option is B 8
$\frac{1}{2} m v^{2} = n (F . d)$
$\Rightarrow n \propto v^{2}$
Thus,
If v is doubled, n will become four times.
Therefore the bullet will penetrate 8 planks.