A bullet moving with a speed of $100 m s^{- 1}$ can just penetrate two planks of equal thickness. Then, the number of such planks penetrated by the same bullet when the speed is doubled will be :

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Solution

The correct option is D 8
Since $K = \frac{1}{2} m v^{2}$
when the speed is doubled, the kinetic energy of the bullet becomes four times the earlier energy.
Thus it would penetrate four times the number of planks it did earlier.
Thus it would then penetrate $4 \times 2 = 8$ planks

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A bullet moving with a speed of 100ms−1 can just penetrate two planks of equal thickness. Then, the number of such planks penetrated by the same bullet when the speed is doubled will be :

The correct option is D 8Since K=12mv2when the speed is doubled, the kinetic energy of the bullet becomes four times the earlier energy.Thus it would penetrate four times the number of planks it did earlier.Thus it would then penetrate 4×2=8 planks

A bullet moving with a speed of $100 m s^{- 1}$ can just penetrate two planks of equal thickness. Then, the number of such planks penetrated by the same bullet when the speed is doubled will be :

The correct option is D 8
Since $K = \frac{1}{2} m v^{2}$
when the speed is doubled, the kinetic energy of the bullet becomes four times the earlier energy.
Thus it would penetrate four times the number of planks it did earlier.
Thus it would then penetrate $4 \times 2 = 8$ planks