A bullet moving with speed $100 m/s$ strikes a block and get embedded into it. If mass of the block is nine times that of the bullet, find the impulse imparted by the bullet to the block (in $Ns$ ), given mass of the bullet is $m kg$ .

100 m

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90 m

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10 m

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110 m

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Solution

The correct option is B $90 m$
Given mass of the bullet is $m kg$ ,
Therefore, mass of the block is $9 m kg$
Initial velocity of bullet, $v_{1} = 100 m/s$
Let the common velocity of bullet + block $= v_{2}$

Applying momentum conservation,
$m_{1} v_{1} = m_{2} v_{2}$
$m \times 100 = (m + 9 m) v_{2}$
$100 m = 10 m v_{2}$
or $v_{2} = 10 m/s$

Therefore, impulse imparted by the bullet on the block, $J = 9 m Δ v$
$J = 9 m (10 - 0)$
$J = 90 m Ns$

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Standard XII Physics

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A bullet moving with speed 100 m/s strikes a block and get embedded into it. If mass of the block is nine times that of the bullet, find the impulse imparted by the bullet to the block (in Ns), given mass of the bullet is m kg.

A bullet moving with speed $100 m/s$ strikes a block and get embedded into it. If mass of the block is nine times that of the bullet, find the impulse imparted by the bullet to the block (in $Ns$ ), given mass of the bullet is $m kg$ .