A bullet of 10g strikes on a sand bag with speed of 1000m/s and stop after travelling 5cm inside the bag. Calculate :-

a) The resistive force exerted by the sand on the bullet
b) The time taken by the bullet to come to rest.

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Solution

Mass of bullet should be =10gm=0.01kg
initial velocity (U)of bullet=1000m/s
final velocity (V)=0m/s(because it has stopped after striking sand)
displacement of bullet=5cm=0.05m
a)using 2as=V ²-U²
2(a)(0.05)=0²-1000²
2a(5/100)=-1000000
2a(1/20)=-1000000
a(1/10)=-1000000
a=-10000000=-10power7
acceleration of bullet is -10power7or -10000000
by using F=ma
F=0.01(10000000)
F=1/100(10000000)
F=-100000N
there fore resistive force of bullet =-100000N

b)by using a=v-u/t
-10000000=0-1000/t
-10000000=-1000/t
-10000=t
or
t=-10⁴seconds

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A bullet of 10g strikes on a sand bag with speed of 1000m/s and stop after travelling 5cm inside the bag. Calculate :- a) The resistive force exerted by the sand on the bullet b) The time taken by the bullet to come to rest.

A bullet of 10g strikes on a sand bag with speed of 1000m/s and stop after travelling 5cm inside the bag. Calculate :-

a) The resistive force exerted by the sand on the bullet
b) The time taken by the bullet to come to rest.