A bullet of 5 g is fired from a pistol of 1.5 kg. If the recoil velocity of pistol is $1.5 m s^{- 1}$ , what is the final momentum of the pistol?

10 k g m s^{- 1}

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2.5 k g m s^{- 1}

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1.5 k g m s^{- 1}

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2.25 k g m s^{- 1}

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Solution

The correct option is D $2.25 k g m s^{- 1}$
Given, recoil velocity of the pistol, $v = 1.5 m s^{- 1}$ and mass of the pistol, $m = 1.5 k g$
Let 'p' be the final momentum of the pistol.
We know, $p = m \times v$ $= 1.5 \times 1.5 = 2.25 k g m s^{- 1}$

Therefore, final momentum of the pistol is $2.25 k g m s^{- 1}$

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