A bullet of mass $0.01 k g$ is fired from a gun weighing $5.0 k g$ . If the initial speed of the bullet is $250 m / s$ , calculate the speed with which the gun recoils.

- 0.50 m / s

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- 0.25 m / s

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+ 0.05 m / s

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+ 0.25 m / s

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Solution

The correct option is A $- 0.50 m / s$
According to momentum conservation :
$M_{1} V_{1} = M_{2} V_{2}$
So, $0.01 \times 250 = 5 \times V_{2}$ ( V2 is speed of gun recoil)
so $V_{2} = 2.5 / 5 = 0.5 m / s$
Hence recoil velocity is $- 0.50 m / s$

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