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Instantaneous Force and Impulse

A bullet of m...

Question

A bullet of mass 0.1 kg moving horizontally with a velocity of 20 m/s strikes a target and brought to rest in 0.1 s. Find the impulse and average force of impact.

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Solution

Initial momentum $P_{i} = m u = 0.1 \times 20 = 2 k g m / s$
Final momentum $P_{f} = 0$
Impulse $I = | P_{f} - P_{i} | = | 0 - 2 | = 2 k g m / s$
Average force $F = \frac{I}{Δ t} = \frac{2}{0.1} = 20 N$

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