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Conservation of Momentum

A bullet of m...

Question

A bullet of mass $0.1 k g$ moving horizontally with a velocity of $20 m / s$ strikes a stationary target & is brought to rest in $0.1 s$ . find the impulse & average force of impact

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Solution

m=0.1kg
vi=20m/s
vf=0m/s
t=0.1s
I=?
Fav=?
solution:
Fav=ma
=m(deltav/delta t)
=0.1(20/0.1)
* F=20N
now
impulse =F×t
=20×0.1
=2Ns

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