MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Conservation of Momentum

A bullet of m...

Question

A bullet of mass $0.1 k g$ moving horizontally with a velocity of $20 m / s$ strikes a stationary target & is brought to rest in $0.1 s$ . find the impulse & average force of impact

Open in App

Solution

m=0.1kg
vi=20m/s
vf=0m/s
t=0.1s
I=?
Fav=?
solution:
Fav=ma
=m(deltav/delta t)
=0.1(20/0.1)
* F=20N
now
impulse =F×t
=20×0.1
=2Ns

Suggest Corrections

thumbs-up

0

Similar questions

Q. A bullet of mass 0.1 kg moving horizontally with a velocity of 20 m/s strikes a target and brought to rest in 0.1 s. Find the impulse and average force of impact.

Q. A bullet of mass

25 g

moving with a velocity of

150 m / s

a strikes a target and is brought to rest in

\frac{1}{100}

of second. What is the impulse?

Q. A bullet of mass 60 g moving with a velocity of

500 m s^{- 1}

is brought to rest in 0.01 s. Find the impulse and the average force of the blow.

Q. A bullet of mass

20

g

is moving with a speed of

150

m s^{- 1}

. It strikes a target and is brought to rest after piercing

10

c m

into it. Calculate the average force of resistance offered by the target.

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Conservation of Momentum

PHYSICS

Watch in App

explore_more_icon

Explore more

Conservation of Momentum

Standard IX Physics

Join BYJU'S Learning Program

CrossIcon