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Question

A bullet of mass 0.4g moving with a speed of 600m/s penetrates a heavy wooden block. It stops after a penetration of 50cm. The resistive force exerted by the block on the bullet is

A
1440N
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B
1480
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C
270N
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D
none
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Solution

The correct option is D none
Given:
Mass=.4 g=.4/1000 kg
U=600m/s
S= 50cm=.5m
Apply third equation of motion to find out the resistive acceleration exerted by block on wood
v2=u2+2as
0=360000+2a×0.5
a=360000m/s2

Resistive force =m×a=360000×0.41000=144N


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