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Second Law of Motion

A bullet of m...

Question

A bullet of mass 1 kg is fired and gets embedded into a block of wood of mass 1 kg initially at rest. The velocity of the bullet before collision is 90 m/s . What is the velocity of the system after collision. Calculate the kinetic energy before and after the collision . Is it an elastic collision or inelastic collision . How much energy is lost in collision .

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Solution

Dear Student
$M a s s o f b u l l e t = 1 K g M a s s o f w o o d = 1 K g v e l o c i t y o f b u l l e t = 90 m s^{- 1} B y c o n s e r v a t i o n o f m o m e n t u m m 1 v 1 + m 2 v 2 = (m 1 + m 2) V v 2 = 0 1 \times 90 = (1 + 1) \times V V = 45 m s^{- 1} T h i s t h e v e l o c i t y o f c o m b i n e d s y s t e m K i n e t i c e n e r g y = 1 / 2 \times 1 \times 90 \times 90 = 4050 J F i n a l k i n e t i c e n e r g y = 1 / 2 \times 45 \times 45 = 2025 J L o s s i n k i n e t i c e n e r g y = 4045 - 2025 = 2025 J R e g a r d s$

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