A bullet of mass $10 g$ strikes a fixed target and penetrates $8 c m$ into it before coming to rest. if the average force of resistance offered by the target is $100 N$ , with what velocity does it strike?

100 m / s

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20 m / s

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30 m / s

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40 m / s

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Solution

The correct option is D $40 m / s$
Given,
$m = 10 g = 0.01 k g$
$s = 8 c m = 0.08 m$
$u = ?$
$v = 0 m / s$
$F = 100 N$
Resistance force, $F = - m a$
$a = - \frac{F}{m} = - \frac{100}{0.01} = - 10000 m / s^{2}$
From 3rd equation of motion,
$2 a s = v^{2} - u^{2}$
$- 2 \times 0.08 \times 10000 = 0^{2} - u^{2}$
$u^{2} = 1600$
$u = \sqrt{1600} = 40 m / s$
The correct option is D.

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A bullet of mass 10g strikes a fixed target and penetrates 8cm into it before coming to rest. if the average force of resistance offered by the target is 100N, with what velocity does it strike?

The correct option is D 40m/sGiven,m=10g=0.01kgs=8cm=0.08mu=?v=0m/sF=100NResistance force, F=−maa=−Fm=−1000.01=−10000m/s2From 3rd equation of motion,2as=v2−u2−2×0.08×10000=02−u2u2=1600u=√1600=40m/sThe correct option is D.

A bullet of mass $10 g$ strikes a fixed target and penetrates $8 c m$ into it before coming to rest. if the average force of resistance offered by the target is $100 N$ , with what velocity does it strike?