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Question
A bullet of mass 10 g travelling horizontally with a velocity of 150 m s−1 strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the magnitude of the force exerted by the wooden block on the bullet and the distance of penetration of the bullet into the block.
A bullet of mass 10 g travelling horizontally with a velocity of 150 m s−1 strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the magnitude of the force exerted by the wooden block on the bullet and the distance of penetration of the bullet into the block.
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Solution
The correct option is B 50 N and 2.25 m
The force exerted on the bullet,F=Change in momentumtimeF=10×10−3 kg(0−150) m s−10.03 s
F = - 50 NThe acceleration of the bullet, a = −5000 m s−2v2 = u2 + 2as0 = (−150)2 − 2(5000)s22500 = −10000 ss = 2.25 m
The force exerted on the bullet,F=Change in momentumtimeF=10×10−3 kg(0−150) m s−10.03 s
F = - 50 NThe acceleration of the bullet, a = −5000 m s−2v2 = u2 + 2as0 = (−150)2 − 2(5000)s22500 = −10000 ss = 2.25 m