A bullet of mass 10 gm hits a fixed target and penetrates through 8 cm in it before coming to rest. If the average resistance offered by the target is 100N, the velocity with which the bullet hits the target is,

20 m/s

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25 m/s

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40 m/s

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50 m/s

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Solution

The correct option is C 40 m/s
Retardation of bullet = $\frac{100}{0.01} = 10000 m / s^{2}$

Using third equation of motion
$v^{2} - u^{2} = 2 a s$
We have,
$0^{2} - u^{2} = 2 \times (- 10000) \times 0.08$

$\Rightarrow u^{2} = 1600$
$\Rightarrow u = 40 m / s$

Therefore, C is correct option.

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A bullet of mass 10 gm hits a fixed target and penetrates through 8 cm in it before coming to rest. If the average resistance offered by the target is 100N, the velocity with which the bullet hits the target is,

The correct option is C 40 m/sRetardation of bullet = 1000.01=10000m/s2Using third equation of motion v2−u2=2asWe have,02−u2=2×(−10000)×0.08⇒u2=1600⇒u=40m/sTherefore, C is correct option.

The correct option is C 40 m/s
Retardation of bullet = $\frac{100}{0.01} = 10000 m / s^{2}$

Using third equation of motion
$v^{2} - u^{2} = 2 a s$
We have,
$0^{2} - u^{2} = 2 \times (- 10000) \times 0.08$

$\Rightarrow u^{2} = 1600$
$\Rightarrow u = 40 m / s$

Therefore, C is correct option.