A bullet of mass 10 gram is fired at a speed of 400 m per second from a gun of mass 4 kg. what is the velocity of the gun?

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Solution

M1=4kg (mass of gun) and M2=0.010kg (mass of bullet)

V1=? ( velocity of gun) and V2=400m/s (velocity of bullet

M1V1=M2V2

4V1=0.010400

V1=4/4

V1=1m/s
Or
Here no external force is acted (neglect air resistant) hence momentum of system(gun+bullet) is conserved
initial momentum = finial momentum
let the recoil velocity of gun = v
0.010 + 40 = 0.01400 + 4v
v = -1m/s
hence gun recoil with velocity 1m/s

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