A bullet of mass 10g moving with a speed of 20m/s hits an ice block of mass 990g kept on a floor and gets stuck in it. How much ice will melt if 50% of the lost KE goes to ice? (initial temperature of the ice block and bullet = 0∘C)
A
0.001g
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B
0.002g
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C
0.003g
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D
0.004g
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Solution
The correct option is C0.003g KE=12mBv2=12×101000×(20)2=12×12×400=2J
So 50% of this is lost which is 1J and this is adsorbed by ice to melt into water.