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Question

A bullet of mass 10 g moving with a speed of 20 m/s hits an ice block of mass 990 g kept on a floor and gets stuck in it. How much ice will melt if 50% of the lost KE goes to ice? (initial temperature of the ice block and bullet = 0C)

A
0.001 g
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B
0.002 g
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C
0.003 g
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D
0.004 g
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Solution

The correct option is C 0.003 g
KE=12mBv2=12×101000×(20)2=12×12×400=2 J

So 50% of this is lost which is 1 J and this is adsorbed by ice to melt into water.


80 cal1 g
80×42 J1g
1 J180×4.2=0.003 g

So 0.003 g of ice melts into water.

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