A bullet of mass 100 g is fired from a gun of mass 20 kg with a velocity of 100 m/s. Identify the velocity of the recoil of the gun.
Applying conservation of momentum on bullet-gun system, we have,
mgvg+mbvb=0
mgvg=−mbvb or vg=−mbvbmg
vg=(−100×10020000)m/s=−0.5m/s, i.e. 0.5m/s in the direction opposite to bullet.