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A bullet of mass 15 g has a speed of 400 m/s. What is its kinetic energy ? If the bullet strikes a thick target and is bought to rest in 2 cm, calculate the average net force acting on the bullet. What happens to the kinetic energy originally in the bullet ?


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Solution



Kinetic energy K.E. = 1 halfmv²

=1 half cross times 15 over 1000 cross times 400 squared

= 1200 J Ans.

The bullet strikes a thick target and is brought to rest in 2 cm, calculate the average net force acting on the bullet.

Work done = Change in K.E.

Final velocity = 0

∵ Change in KE = Kf - Ki = 1200 J

∴ F xd = 1200

(Here, F is the average force)

F equals fraction numerator 1200 over denominator 2 cross times 10 to the power of negative 2 end exponent end fraction

= 6 cross times 10 to the power of 4 N Ans.



The kinetic energy is converted to heat energy


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