A bullet of mass $20 g$ is horizontally fired with a velocity $150 m s^{- 1}$ from a pistol of mass $2 k g$ . What is the recoil velocity of the pistol?

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Solution

Initial momentum of the system is $0$ as it is at rest.
After firing-

$M V = m v$

$⟹ V = \frac{m v}{M} = \frac{0.02 \times 150}{2}$

$⟹ V = 1.5 m / s$

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Similar questions

20 g

150 m / s

2 k g

m_{1} = 20 g (= 0.02 k g)

m_{2} = 2 k g

(u_{1})

(u_{2}) = 0

v_{1} = + 150 m s^{- 1}

1.5 m s^{- 1}

A bullet of $5 g$ is fired from a pistol of $1.5 k g$ . If the recoil speed of pistol is $1.5 m s^{- 1}$ , find the velocity of bullet.

A bullet of 5 $g$ is fired from a pistol of 1.5 kg. If the recoil velocity of a pistol is 1.5 $\frac{m}{s}$ . What is the velocity of the bullet?

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