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Question

A bullet of mass 20 g is moving with a speed of 150 ms−1. It strikes a target and is brought to rest after piercing 10 cm into it. Calculate the average force of resistance offered by the target.

A
2500 N
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B
2000 J
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C
2250 N
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D
2100 J
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Solution

The correct option is C 2250 N
Mass =20 g=0.02 kg
Initial velocity (u)=150 ms1
Final velocity (v)=0 ms1
Distance travelled before coming to rest (s)=10 cm=0.1 m
v2=u22as
0=(150)22a0.1=112500 ms2
f=ma
f=0.02×112500 =2250 N

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