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Question

# A bullet of mass 20 grams moving with a velocity of 100 ms−1 strikes a wooden block of mass 80 grams and gets embedded into it. What is the velocity acquired by the block?

A

10 ms1

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B

30 ms1

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C

20 ms1

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D

50 ms1

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Solution

## The correct option is C 20 ms−1 Here, mass of bullet (m1) = 20 g = 0.02 kg, velocity of bullet (v1) = 100 ms−1, mass of wooden block = 80 g = 0.08 kg. Momentum of the bullet = m1×v1 = 0.02×100 kg ms−1 Mass of wooden block along with embedded bullet (m2) = 0.02 + 0.08 = 0.10 kg Velocity of wooden block + bullet = v2 By applying law of conservation of momentum, m1×v1 = m2×v2 0.02×100 = 0.10×v2 ⇒v2 = 0.02×1000.10 = 20 ms−1

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