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Question

A bullet of mass 20 g strikes a pendulum of mass 5 kg. The center of mass of the pendulum rises a vertical distance of 10 cm. If the bullet gets embedded into the pendulum, calculate the initial speed of the bullet.

A
354.97 m/s
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B
340.97 m/s
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C
250.41 m/s
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D
251 m/s
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Solution

The correct option is A 354.97 m/s
Given: Mass of bullet, m1=0.02 kg
Mass of pendulum, m2=5 kg
Center of mass of pendulum rises to a height h=0.1 m

Let speed of bullet =u1
Pendulum is at rest, so u2=0
Let the common velocity of bullet and pendulum =v
v=m1u1+m2u2m1+m2=0.02×u1+5×05+0.02
i.e v=u1251 ... (1)

After bullet gets embedded, applying conservation of energy
(m1+m2)gh=12(m1+m2)v2
v=2gh=2×10×0.1
v=2 m/s
From eq.(1)
2=u1251
or u1=354.97 m/s

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