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Question

A bullet of mass 200 g fired with a velocity of 200 m/s, hits a block of mass 2 kg moving with a velocity of 10 m/s. After hitting the block, the bullet lodges into it. What is the velocity of the combined system? Assume that the collision is perfectly inelastic.

A
27.27 m/s
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B
20 m/s
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C
54.54 m/s
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D
36.36 m/s
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Solution

The correct option is A 27.27 m/s
Before collision

After collision

Applying conservation of linear momentum before and after collision.
m1u1+m2u2=(m1+m2)v
0.200×200+2×10=(0.2+2)v
v=27.27 m/s
Velocity of block after collision is 27.27 m/s
The correct option is (a).

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