A bullet of mass 25 g is fired with velocity 400 ms−1 at a bag of sand of mass 4.975 kg suspended by a rope and gets embedded into it. What is the velocity gained by the bag?
A
0.2 ms−1
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B
4 ms−1
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C
0.4 ms−1
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D
2 ms−1
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Solution
The correct option is D 2 ms−1 conserving the momentum of system. 0.025∗400+4.975∗0.0=(4.975+0.025)∗vv=10/5=2m/s