A bullet of mass $25 g$ moving with a velocity of $150 m / s$ a strikes a target and is brought to rest in $\frac{1}{100}$ of second. What is the impulse?

- 15 N s

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- 3.75 N s

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- 18.75 N s

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- 7.5 N s

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Solution

The correct option is A $- 3.75 N s$
Given,
$m = 25 g$
$u = 150 m / s$
$v = 0 m / s$
$t = \frac{1}{100} s e c$
From 1st equation of motion,
$v = u + a t$
$0 = 150 + a \frac{1}{100}$
$150 = - \frac{a}{100}$
$a = - 15000 m / s^{2}$
Force, $F = m a$
$F = - \frac{25}{1000} \times 15000 = - 375 N$
Impulse, $I = F o r c e \times t i m e = F t$
$I = - 375 \times \frac{1}{100}$
$I = - 3.75 N s$
The correct option is B.

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A bullet of mass 25 g moving with a velocity of 150 m/s a strikes a target and is brought to rest in 1100 of second. What is the impulse?

The correct option is A −3.75 NsGiven,m=25gu=150m/sv=0m/st=1100secFrom 1st equation of motion, v=u+at0=150+a1100150=−a100a=−15000m/s2Force, F=maF=−251000×15000=−375NImpulse, I=Force×time=FtI=−375×1100I=−3.75NsThe correct option is B.

A bullet of mass $25 g$ moving with a velocity of $150 m / s$ a strikes a target and is brought to rest in $\frac{1}{100}$ of second. What is the impulse?